幅相频率特性(Nyquist图)

比例环节

        G(s)=K                    G(jω)=K~~~~~~~~G(s) = K~~~~~~~~~~~~~~~~~~~~G(j\omega) = K

        G=K                      G=0~~~~~~~~|G| = K~~~~~~~~~~~~~~~~~~~~~~\angle G = 0^\circ

  

微分环节

        G(s)=s                    G(jω)=jω~~~~~~~~G(s) = s~~~~~~~~~~~~~~~~~~~~G(j\omega) = j\omega

        G=ω                      G=90~~~~~~~~|G| = \omega~~~~~~~~~~~~~~~~~~~~~~\angle G = 90^\circ

  

积分环节

        G(s)=1s                    G(jω)=1jω~~~~~~~~G(s) = \frac{1}{s}~~~~~~~~~~~~~~~~~~~~G(j\omega) = \frac{1}{j\omega}

        G=1ω                      G=90~~~~~~~~|G| = \frac{1}{\omega}~~~~~~~~~~~~~~~~~~~~~~\angle G = -90^\circ

  

惯性环节

        G(s)=1Ts+1              G(jω)=1jωT+1~~~~~~~~G(s) = \frac{1}{Ts+1}~~~~~~~~~~~~~~G(j\omega) = \frac{1}{j\omega T+1}

        G=11+ω2T2            G=arctan ωT~~~~~~~~|G| = \frac{1}{\sqrt{1+\omega^2T^2}}~~~~~~~~~~~~\angle G = -arctan~\omega T

  

一阶微分环节

        G(s)=Ts+1           G(jω)=jωT+1~~~~~~~~G(s) = Ts+1~~~~~~~~~~~G(j\omega) = j\omega T+1

        G=1+ω2T2      G=arctan ωT~~~~~~~~|G| = \sqrt{1+\omega^2T^2}~~~~~~\angle G = arctan~\omega T

  

振荡环节